11010110020121 has 2 divisors, whose sum is σ = 11010110020122. Its totient is φ = 11010110020120.

The previous prime is 11010110020097. The next prime is 11010110020123. The reversal of 11010110020121 is 12102001101011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10235930004496 + 774180015625 = 3199364^2 + 879875^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11010110020121 is a prime.

Together with 11010110020123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11010110020123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505055010060 + 5505055010061.

It is an arithmetic number, because the mean of its divisors is an integer number (5505055010061).

Almost surely, 2^{11010110020121} is an apocalyptic number.

It is an amenable number.

11010110020121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010110020121 is an equidigital number, since it uses as much as digits as its factorization.

11010110020121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 11010110020121 its reverse (12102001101011), we get a palindrome (23112111121132).

The spelling of 11010110020121 in words is "eleven trillion, ten billion, one hundred ten million, twenty thousand, one hundred twenty-one".