Search a number
-
+
11010156413 is a prime number
BaseRepresentation
bin10100100000100000…
…11010011101111101
31001102022112220012212
422100100122131331
5140022100001123
65020305510205
7536561533244
oct122020323575
931368486185
1011010156413
11473aa45523
122173342365
131066072469
1476639595b
154468e8878
hex29041a77d

11010156413 has 2 divisors, whose sum is σ = 11010156414. Its totient is φ = 11010156412.

The previous prime is 11010156397. The next prime is 11010156427. The reversal of 11010156413 is 31465101011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8896639684 + 2113516729 = 94322^2 + 45973^2 .

It is an emirp because it is prime and its reverse (31465101011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11010156413 - 24 = 11010156397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010156433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505078206 + 5505078207.

It is an arithmetic number, because the mean of its divisors is an integer number (5505078207).

Almost surely, 211010156413 is an apocalyptic number.

It is an amenable number.

11010156413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010156413 is an equidigital number, since it uses as much as digits as its factorization.

11010156413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 11010156413 its reverse (31465101011), we get a palindrome (42475257424).

The spelling of 11010156413 in words is "eleven billion, ten million, one hundred fifty-six thousand, four hundred thirteen".