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11010244133 = 71572892019
BaseRepresentation
bin10100100000100001…
…01111111000100101
31001102022201100112202
422100100233320211
5140022110303013
65020311424245
7536562350060
oct122020577045
931368640482
1011010244133
11473aaa5419
122173385085
1310660a3375
147663b98d7
15446914858
hex29042fe25

11010244133 has 4 divisors (see below), whose sum is σ = 12583136160. Its totient is φ = 9437352108.

The previous prime is 11010244129. The next prime is 11010244159. The reversal of 11010244133 is 33144201011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33144201011 = 171949658883.

It is a cyclic number.

It is not a de Polignac number, because 11010244133 - 22 = 11010244129 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11010244103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786446003 + ... + 786446016.

It is an arithmetic number, because the mean of its divisors is an integer number (3145784040).

Almost surely, 211010244133 is an apocalyptic number.

It is an amenable number.

11010244133 is a deficient number, since it is larger than the sum of its proper divisors (1572892027).

11010244133 is an equidigital number, since it uses as much as digits as its factorization.

11010244133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1572892026.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11010244133 its reverse (33144201011), we get a palindrome (44154445144).

The spelling of 11010244133 in words is "eleven billion, ten million, two hundred forty-four thousand, one hundred thirty-three".

Divisors: 1 7 1572892019 11010244133