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110103443143 = 130784241349
BaseRepresentation
bin110011010001010101…
…1010011011011000111
3101112012022001102200121
41212202223103123013
53300442440140033
6122325242522411
710645315552651
oct1464253233307
9345168042617
10110103443143
1142770583511
1219409506407
13a4c8a77975
145486c2d6d1
152ce622c62d
hex19a2ad36c7

110103443143 has 4 divisors (see below), whose sum is σ = 110187685800. Its totient is φ = 110019200488.

The previous prime is 110103443141. The next prime is 110103443147. The reversal of 110103443143 is 341344301011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341344301011 = 748763471573.

It is a cyclic number.

It is not a de Polignac number, because 110103443143 - 21 = 110103443141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110103443141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42119368 + ... + 42121981.

It is an arithmetic number, because the mean of its divisors is an integer number (27546921450).

Almost surely, 2110103443143 is an apocalyptic number.

110103443143 is a deficient number, since it is larger than the sum of its proper divisors (84242657).

110103443143 is an equidigital number, since it uses as much as digits as its factorization.

110103443143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84242656.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 110103443143 its reverse (341344301011), we get a palindrome (451447744154).

The spelling of 110103443143 in words is "one hundred ten billion, one hundred three million, four hundred forty-three thousand, one hundred forty-three".

Divisors: 1 1307 84241349 110103443143