Base | Representation |
---|---|
bin | 1010000000111011001011… |
… | …0000000000110001000111 |
3 | 1102222122022112022011122111 |
4 | 2200032302300000301013 |
5 | 2420401012012011101 |
6 | 35230214510041451 |
7 | 2214342563445316 |
oct | 240166260006107 |
9 | 42878275264574 |
10 | 11011000110151 |
11 | 3565814562538 |
12 | 129a0097a9287 |
13 | 61b443389882 |
14 | 2a0d1447427d |
15 | 14164c26b251 |
hex | a03b2c00c47 |
11011000110151 has 2 divisors, whose sum is σ = 11011000110152. Its totient is φ = 11011000110150.
The previous prime is 11011000110119. The next prime is 11011000110157. The reversal of 11011000110151 is 15101100011011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11011000110151 - 25 = 11011000110119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11011000110157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505500055075 + 5505500055076.
It is an arithmetic number, because the mean of its divisors is an integer number (5505500055076).
Almost surely, 211011000110151 is an apocalyptic number.
11011000110151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011000110151 is an equidigital number, since it uses as much as digits as its factorization.
11011000110151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 13.
Adding to 11011000110151 its reverse (15101100011011), we get a palindrome (26112100121162).
The spelling of 11011000110151 in words is "eleven trillion, eleven billion, one hundred ten thousand, one hundred fifty-one".
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