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110110100101031 is a prime number
BaseRepresentation
bin11001000010010100000001…
…011001110001011110100111
3112102212102102012022102021202
4121002110001121301132213
5103413020441111213111
61030103514235033115
732123122633113002
oct3102240131613647
9472772365272252
10110110100101031
11320a2481a40728
12104240a989b79b
134959451448b34
141d29500540539
15cae33a4ceb3b
hex6425016717a7

110110100101031 has 2 divisors, whose sum is σ = 110110100101032. Its totient is φ = 110110100101030.

The previous prime is 110110100100947. The next prime is 110110100101033. The reversal of 110110100101031 is 130101001011011.

It is a strong prime.

It is an emirp because it is prime and its reverse (130101001011011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110110100101031 - 230 = 110109026359207 is a prime.

It is a super-2 number, since 2×1101101001010312 (a number of 29 digits) contains 22 as substring.

Together with 110110100101033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110110100101033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055050050515 + 55055050050516.

It is an arithmetic number, because the mean of its divisors is an integer number (55055050050516).

Almost surely, 2110110100101031 is an apocalyptic number.

110110100101031 is a deficient number, since it is larger than the sum of its proper divisors (1).

110110100101031 is an equidigital number, since it uses as much as digits as its factorization.

110110100101031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 110110100101031 its reverse (130101001011011), we get a palindrome (240211101112042).

The spelling of 110110100101031 in words is "one hundred ten trillion, one hundred ten billion, one hundred million, one hundred one thousand, thirty-one".