11012111111117 has 2 divisors, whose sum is σ = 11012111111118. Its totient is φ = 11012111111116.

The previous prime is 11012111110963. The next prime is 11012111111119. The reversal of 11012111111117 is 71111111121011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8340001064836 + 2672110046281 = 2887906^2 + 1634659^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012111111117 - 2⁴⁰ = 9912599483341 is a prime.

It is a super-2 number, since 2×11012111111117² (a number of 27 digits) contains 22 as substring.

Together with 11012111111119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11012111111119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506055555558 + 5506055555559.

It is an arithmetic number, because the mean of its divisors is an integer number (5506055555559).

Almost surely, 2^{11012111111117} is an apocalyptic number.

It is an amenable number.

11012111111117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012111111117 is an equidigital number, since it uses as much as digits as its factorization.

11012111111117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 20.

Adding to 11012111111117 its reverse (71111111121011), we get a palindrome (82123222232128).

The spelling of 11012111111117 in words is "eleven trillion, twelve billion, one hundred eleven million, one hundred eleven thousand, one hundred seventeen".