Base | Representation |
---|---|
bin | 11001000010011110010111… |
… | …101010100111011000101101 |
3 | 112102220111002112111020202112 |
4 | 121002132113222213120231 |
5 | 103413211220011030013 |
6 | 1030112552544533405 |
7 | 32123665160352026 |
oct | 3102362752473055 |
9 | 472814075436675 |
10 | 110121211033133 |
11 | 320a7163857443 |
12 | 1042628a921265 |
13 | 495a502343b81 |
14 | 1d29c76049c4d |
15 | cae78ab82ba8 |
hex | 642797aa762d |
110121211033133 has 8 divisors (see below), whose sum is σ = 115001983166208. Its totient is φ = 105248180016144.
The previous prime is 110121211033129. The next prime is 110121211033151. The reversal of 110121211033133 is 331330112121011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 110121211033133 - 22 = 110121211033129 is a prime.
It is a super-2 number, since 2×1101212110331332 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110121211033099 and 110121211033108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110121211033123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1935249941 + ... + 1935306842.
It is an arithmetic number, because the mean of its divisors is an integer number (14375247895776).
Almost surely, 2110121211033133 is an apocalyptic number.
It is an amenable number.
110121211033133 is a deficient number, since it is larger than the sum of its proper divisors (4880772133075).
110121211033133 is a wasteful number, since it uses less digits than its factorization.
110121211033133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3870558043.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 110121211033133 its reverse (331330112121011), we get a palindrome (441451323154144).
The spelling of 110121211033133 in words is "one hundred ten trillion, one hundred twenty-one billion, two hundred eleven million, thirty-three thousand, one hundred thirty-three".
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