1101230111983 has 2 divisors, whose sum is σ = 1101230111984. Its totient is φ = 1101230111982.

The previous prime is 1101230111981. The next prime is 1101230112053. The reversal of 1101230111983 is 3891110321011.

It is a weak prime.

It is an emirp because it is prime and its reverse (3891110321011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101230111983 - 2¹ = 1101230111981 is a prime.

Together with 1101230111981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101230111981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550615055991 + 550615055992.

It is an arithmetic number, because the mean of its divisors is an integer number (550615055992).

Almost surely, 2^{1101230111983} is an apocalyptic number.

1101230111983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101230111983 is an equidigital number, since it uses as much as digits as its factorization.

1101230111983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 31.

Adding to 1101230111983 its reverse (3891110321011), we get a palindrome (4992340432994).

The spelling of 1101230111983 in words is "one trillion, one hundred one billion, two hundred thirty million, one hundred eleven thousand, nine hundred eighty-three".