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11012413021423 = 11291011677863
BaseRepresentation
bin1010000001000000011011…
…1101110101110011101111
31102222202221222221111112121
42200100012331311303233
52420411410213141143
635231011021413411
72214422601134212
oct240200675656357
942882858844477
1011012413021423
11356637a06a700
12129a342a0a267
1361b60a009048
142a1009d87779
151416d13117ed
hexa0406f75cef

11012413021423 has 6 divisors (see below), whose sum is σ = 12104553155912. Its totient is φ = 10011284564820.

The previous prime is 11012413021397. The next prime is 11012413021429. The reversal of 11012413021423 is 32412031421011.

It is a de Polignac number, because none of the positive numbers 2k-11012413021423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11012413021429) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 45505838811 + ... + 45505839052.

Almost surely, 211012413021423 is an apocalyptic number.

11012413021423 is a deficient number, since it is larger than the sum of its proper divisors (1092140134489).

11012413021423 is an equidigital number, since it uses as much as digits as its factorization.

11012413021423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91011677885 (or 91011677874 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 11012413021423 its reverse (32412031421011), we get a palindrome (43424444442434).

The spelling of 11012413021423 in words is "eleven trillion, twelve billion, four hundred thirteen million, twenty-one thousand, four hundred twenty-three".

Divisors: 1 11 121 91011677863 1001128456493 11012413021423