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11013004112143 = 114361937614389
BaseRepresentation
bin1010000001000010101000…
…1100101011000100001111
31102222211111012012000120111
42200100222030223010033
52420414113023042033
635231145414500451
72214443336255605
oct240205214530417
942884435160514
1011013004112143
113566652792930
12129a488964727
1361b6a2605677
142a1064691875
1514171816e7cd
hexa042a32b10f

11013004112143 has 16 divisors (see below), whose sum is σ = 12313446710400. Its totient is φ = 9763190549280.

The previous prime is 11013004112141. The next prime is 11013004112147. The reversal of 11013004112143 is 34121140031011.

It is a cyclic number.

It is not a de Polignac number, because 11013004112143 - 21 = 11013004112141 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013004112141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18514408 + ... + 19099981.

It is an arithmetic number, because the mean of its divisors is an integer number (769590419400).

Almost surely, 211013004112143 is an apocalyptic number.

11013004112143 is a deficient number, since it is larger than the sum of its proper divisors (1300442598257).

11013004112143 is a wasteful number, since it uses less digits than its factorization.

11013004112143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37615062.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 11013004112143 its reverse (34121140031011), we get a palindrome (45134144143154).

The spelling of 11013004112143 in words is "eleven trillion, thirteen billion, four million, one hundred twelve thousand, one hundred forty-three".

Divisors: 1 11 43 473 619 6809 26617 292787 37614389 413758279 1617418727 17791605997 23283306791 256116374701 1001182192013 11013004112143