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1101310312301 is a prime number
BaseRepresentation
bin10000000001101011001…
…101011011111101101101
310220021200012122112021222
4100001223031123331231
5121020440414443201
62201533542033125
7142365332125013
oct20015315337555
93807605575258
101101310312301
11395076a62021
121595367187a5
137cb123b3cb4
143b4375108b3
151d9aaa2b91b
hex1006b35bf6d

1101310312301 has 2 divisors, whose sum is σ = 1101310312302. Its totient is φ = 1101310312300.

The previous prime is 1101310312247. The next prime is 1101310312303. The reversal of 1101310312301 is 1032130131011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1030578250276 + 70732062025 = 1015174^2 + 265955^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101310312301 - 234 = 1084130443117 is a prime.

Together with 1101310312303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1101310312301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101310312303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550655156150 + 550655156151.

It is an arithmetic number, because the mean of its divisors is an integer number (550655156151).

Almost surely, 21101310312301 is an apocalyptic number.

It is an amenable number.

1101310312301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101310312301 is an equidigital number, since it uses as much as digits as its factorization.

1101310312301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1101310312301 its reverse (1032130131011), we get a palindrome (2133440443312).

The spelling of 1101310312301 in words is "one trillion, one hundred one billion, three hundred ten million, three hundred twelve thousand, three hundred one".