Base | Representation |
---|---|
bin | 10100100000110111… |
… | …01110100001100011 |
3 | 1001102112010120102212 |
4 | 22100123232201203 |
5 | 140023324402042 |
6 | 5020453232335 |
7 | 536625664556 |
oct | 122033564143 |
9 | 31375116385 |
10 | 11013122147 |
11 | 4741690745 |
12 | 21743326ab |
13 | 1066870331 |
14 | 76692869d |
15 | 446cd2482 |
hex | 2906ee863 |
11013122147 has 2 divisors, whose sum is σ = 11013122148. Its totient is φ = 11013122146.
The previous prime is 11013122101. The next prime is 11013122149. The reversal of 11013122147 is 74122131011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11013122147 - 26 = 11013122083 is a prime.
Together with 11013122149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11013122149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506561073 + 5506561074.
It is an arithmetic number, because the mean of its divisors is an integer number (5506561074).
Almost surely, 211013122147 is an apocalyptic number.
11013122147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013122147 is an equidigital number, since it uses as much as digits as its factorization.
11013122147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 11013122147 its reverse (74122131011), we get a palindrome (85135253158).
The spelling of 11013122147 in words is "eleven billion, thirteen million, one hundred twenty-two thousand, one hundred forty-seven".
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