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1101323453255 = 5220264690651
BaseRepresentation
bin10000000001101011111…
…111100100001101000111
310220021201010101011021222
4100001223333210031013
5121021002301001010
62201535131430555
7142365551615564
oct20015377441507
93807633334258
101101323453255
11395083418013
1215953abb545b
137cb150353cc
143b43917186b
151d9abc75355
hex1006bfe4347

1101323453255 has 4 divisors (see below), whose sum is σ = 1321588143912. Its totient is φ = 881058762600.

The previous prime is 1101323453221. The next prime is 1101323453261. The reversal of 1101323453255 is 5523543231011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1101323453255 - 234 = 1084143584071 is a prime.

It is a super-3 number, since 3×11013234532553 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110132345321 + ... + 110132345330.

It is an arithmetic number, because the mean of its divisors is an integer number (330397035978).

Almost surely, 21101323453255 is an apocalyptic number.

1101323453255 is a deficient number, since it is larger than the sum of its proper divisors (220264690657).

1101323453255 is an equidigital number, since it uses as much as digits as its factorization.

1101323453255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 220264690656.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 1101323453255 its reverse (5523543231011), we get a palindrome (6624866684266).

The spelling of 1101323453255 in words is "one trillion, one hundred one billion, three hundred twenty-three million, four hundred fifty-three thousand, two hundred fifty-five".

Divisors: 1 5 220264690651 1101323453255