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1101421313141 is a prime number
BaseRepresentation
bin10000000001110001110…
…100110111110001110101
310220021221221111221211012
4100001301310313301311
5121021202324010031
62201552545122005
7142401150455432
oct20016164676165
93807857457735
101101421313141
11395123687656
12159567929305
137cb2c3a9a76
143b448166b89
151d9b5655b2b
hex10071d37c75

1101421313141 has 2 divisors, whose sum is σ = 1101421313142. Its totient is φ = 1101421313140.

The previous prime is 1101421313131. The next prime is 1101421313191. The reversal of 1101421313141 is 1413131241011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 590675250916 + 510746062225 = 768554^2 + 714665^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101421313141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101421313131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550710656570 + 550710656571.

It is an arithmetic number, because the mean of its divisors is an integer number (550710656571).

Almost surely, 21101421313141 is an apocalyptic number.

It is an amenable number.

1101421313141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101421313141 is an equidigital number, since it uses as much as digits as its factorization.

1101421313141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 1101421313141 its reverse (1413131241011), we get a palindrome (2514552554152).

The spelling of 1101421313141 in words is "one trillion, one hundred one billion, four hundred twenty-one million, three hundred thirteen thousand, one hundred forty-one".