1101511345045 has 4 divisors (see below), whose sum is σ = 1321813614060. Its totient is φ = 881209076032.

The previous prime is 1101511345003. The next prime is 1101511345091. The reversal of 1101511345045 is 5405431151011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 313494728836 + 788016616209 = 559906^2 + 887703^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101511345045 - 2¹⁵ = 1101511312277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1101511344998 and 1101511345016.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110151134500 + ... + 110151134509.

It is an arithmetic number, because the mean of its divisors is an integer number (330453403515).

Almost surely, 2^{1101511345045} is an apocalyptic number.

It is an amenable number.

1101511345045 is a deficient number, since it is larger than the sum of its proper divisors (220302269015).

1101511345045 is an equidigital number, since it uses as much as digits as its factorization.

1101511345045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220302269014.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 1101511345045 its reverse (5405431151011), we get a palindrome (6506942496056).

The spelling of 1101511345045 in words is "one trillion, one hundred one billion, five hundred eleven million, three hundred forty-five thousand, forty-five".