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1102002000000 = 273561159283
BaseRepresentation
bin10000000010010100011…
…100000001000010000000
310220100110102011220102220
4100002110130001002000
5121023400003000000
62202130331211040
7142421431306146
oct20022434010200
93810412156386
101102002000000
113953a1444250
121596aa2a6a80
137cbc27a2a65
143b4a1323596
151d9eb60b1a0
hex10094701080

1102002000000 has 896 divisors, whose sum is σ = 4073572857600. Its totient is φ = 261696000000.

The previous prime is 1102001999897. The next prime is 1102002000049. The reversal of 1102002000000 is 2002011.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 3893999859 + ... + 3894000141.

Almost surely, 21102002000000 is an apocalyptic number.

1102002000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1102002000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2036786428800).

1102002000000 is an abundant number, since it is smaller than the sum of its proper divisors (2971570857600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1102002000000 is an frugal number, since it uses more digits than its factorization.

1102002000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400 (or 363 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 6.

Adding to 1102002000000 its reverse (2002011), we get a palindrome (1102004002011).

The spelling of 1102002000000 in words is "one trillion, one hundred two billion, two million", and thus it is an aban number.