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11020130211312 = 243223101181118191
BaseRepresentation
bin1010000001011101001011…
…1100100101010111110000
31110000111212211012100220100
42200113102330211113300
52421023211313230222
635234324455512400
72215115046151125
oct240272274452760
943014784170810
1011020130211312
11356967a234692
12129b937388700
1361c269a8c6b1
142a153cc7474c
151419d3a964ac
hexa05d2f255f0

11020130211312 has 240 divisors, whose sum is σ = 32520341707776. Its totient is φ = 3476763840000.

The previous prime is 11020130211281. The next prime is 11020130211317. The reversal of 11020130211312 is 21311203102011.

11020130211312 is a `hidden beast` number, since 1 + 10 + 2 + 0 + 130 + 211 + 312 = 666.

It is a super-2 number, since 2×110201302113122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11020130211317) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 605792137 + ... + 605810327.

Almost surely, 211020130211312 is an apocalyptic number.

11020130211312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11020130211312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16260170853888).

11020130211312 is an abundant number, since it is smaller than the sum of its proper divisors (21500211496464).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11020130211312 is a wasteful number, since it uses less digits than its factorization.

11020130211312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20140 (or 20131 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 11020130211312 its reverse (21311203102011), we get a palindrome (32331333313323).

The spelling of 11020130211312 in words is "eleven trillion, twenty billion, one hundred thirty million, two hundred eleven thousand, three hundred twelve".