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11020222212017 is a prime number
BaseRepresentation
bin1010000001011101100001…
…1011100010011110110001
31110000112010020022111010212
42200113120123202132301
52421023403341241032
635234341543433505
72215120244145554
oct240273033423661
943015106274125
1011020222212017
113569717162127
12129b962155895
1361c282b62195
142a154b18269b
151419dbbbabb2
hexa05d86e27b1

11020222212017 has 2 divisors, whose sum is σ = 11020222212018. Its totient is φ = 11020222212016.

The previous prime is 11020222211989. The next prime is 11020222212019. The reversal of 11020222212017 is 71021222202011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7796470190656 + 3223752021361 = 2792216^2 + 1795481^2 .

It is a cyclic number.

It is not a de Polignac number, because 11020222212017 - 212 = 11020222207921 is a prime.

Together with 11020222212019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11020222211983 and 11020222212001.

It is not a weakly prime, because it can be changed into another prime (11020222212019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510111106008 + 5510111106009.

It is an arithmetic number, because the mean of its divisors is an integer number (5510111106009).

Almost surely, 211020222212017 is an apocalyptic number.

It is an amenable number.

11020222212017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11020222212017 is an equidigital number, since it uses as much as digits as its factorization.

11020222212017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 11020222212017 its reverse (71021222202011), we get a palindrome (82041444414028).

The spelling of 11020222212017 in words is "eleven trillion, twenty billion, two hundred twenty-two million, two hundred twelve thousand, seventeen".