Base | Representation |
---|---|
bin | 1010000001100000110101… |
… | …0110101000111001000011 |
3 | 1110000121102010001212220211 |
4 | 2200120031112220321003 |
5 | 2421032213142320003 |
6 | 35235010022414551 |
7 | 2215151245222564 |
oct | 240301526507103 |
9 | 43017363055824 |
10 | 11021110120003 |
11 | 356a032385585 |
12 | 129bb6b591457 |
13 | 61c394ab3a19 |
14 | 2a15d307216b |
15 | 141a3eb0996d |
hex | a060d5a8e43 |
11021110120003 has 2 divisors, whose sum is σ = 11021110120004. Its totient is φ = 11021110120002.
The previous prime is 11021110120001. The next prime is 11021110120019. The reversal of 11021110120003 is 30002101112011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11021110120003 - 21 = 11021110120001 is a prime.
Together with 11021110120001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11021110120001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510555060001 + 5510555060002.
It is an arithmetic number, because the mean of its divisors is an integer number (5510555060002).
Almost surely, 211021110120003 is an apocalyptic number.
11021110120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11021110120003 is an equidigital number, since it uses as much as digits as its factorization.
11021110120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11021110120003 its reverse (30002101112011), we get a palindrome (41023211232014).
The spelling of 11021110120003 in words is "eleven trillion, twenty-one billion, one hundred ten million, one hundred twenty thousand, three".
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