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11021120210213 is a prime number
BaseRepresentation
bin1010000001100000110111…
…1101001000010100100101
31110000121102211001112002022
42200120031331020110211
52421032223233211323
635235011022552525
72215151430046241
oct240301575102445
943017384045068
1011021120210213
11356a0380474a3
12129bb72a38745
1361c396c07669
142a15d453b421
15141a4094e4c8
hexa060df48525

11021120210213 has 2 divisors, whose sum is σ = 11021120210214. Its totient is φ = 11021120210212.

The previous prime is 11021120210153. The next prime is 11021120210281. The reversal of 11021120210213 is 31201202112011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9888647522884 + 1132472687329 = 3144622^2 + 1064177^2 .

It is a cyclic number.

It is not a de Polignac number, because 11021120210213 - 210 = 11021120209189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11021120210191 and 11021120210200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11021120210713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510560105106 + 5510560105107.

It is an arithmetic number, because the mean of its divisors is an integer number (5510560105107).

Almost surely, 211021120210213 is an apocalyptic number.

It is an amenable number.

11021120210213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11021120210213 is an equidigital number, since it uses as much as digits as its factorization.

11021120210213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11021120210213 its reverse (31201202112011), we get a palindrome (42222322322224).

The spelling of 11021120210213 in words is "eleven trillion, twenty-one billion, one hundred twenty million, two hundred ten thousand, two hundred thirteen".