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11022131999 is a prime number
BaseRepresentation
bin10100100001111100…
…00110001100011111
31001110011002022122002
422100332012030133
5140033131210444
65021414312515
7540065401424
oct122076061437
931404068562
1011022131999
1147467849aa
12217735873b
1310686a62c8
14767bd1d4b
154479b1d4e
hex290f8631f

11022131999 has 2 divisors, whose sum is σ = 11022132000. Its totient is φ = 11022131998.

The previous prime is 11022131947. The next prime is 11022132001. The reversal of 11022131999 is 99913122011.

11022131999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11022131999 is a prime.

Together with 11022132001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11022131299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511065999 + 5511066000.

It is an arithmetic number, because the mean of its divisors is an integer number (5511066000).

Almost surely, 211022131999 is an apocalyptic number.

11022131999 is a deficient number, since it is larger than the sum of its proper divisors (1).

11022131999 is an equidigital number, since it uses as much as digits as its factorization.

11022131999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8748, while the sum is 38.

The spelling of 11022131999 in words is "eleven billion, twenty-two million, one hundred thirty-one thousand, nine hundred ninety-nine".