Base | Representation |
---|---|
bin | 10000000010100001011… |
… | …111011110100100011111 |
3 | 10220101000200021211100222 |
4 | 100002201133132210133 |
5 | 121024322034324411 |
6 | 2202204153311555 |
7 | 142430031003644 |
oct | 20024137364437 |
9 | 3811020254328 |
10 | 1102221011231 |
11 | 3954a403166a |
12 | 15974b7055bb |
13 | 7cc28c853c2 |
14 | 3b4c2453dcb |
15 | 1da1096d4db |
hex | 100a17de91f |
1102221011231 has 2 divisors, whose sum is σ = 1102221011232. Its totient is φ = 1102221011230.
The previous prime is 1102221011191. The next prime is 1102221011251. The reversal of 1102221011231 is 1321101222011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1321101222011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1102221011231 is a prime.
It is a super-2 number, since 2×11022210112312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102221011251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551110505615 + 551110505616.
It is an arithmetic number, because the mean of its divisors is an integer number (551110505616).
Almost surely, 21102221011231 is an apocalyptic number.
1102221011231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102221011231 is an equidigital number, since it uses as much as digits as its factorization.
1102221011231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1102221011231 its reverse (1321101222011), we get a palindrome (2423322233242).
The spelling of 1102221011231 in words is "one trillion, one hundred two billion, two hundred twenty-one million, eleven thousand, two hundred thirty-one".
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