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11023413551 is a prime number
BaseRepresentation
bin10100100010000101…
…11111000100101111
31001110020111102120222
422101002333010233
5140033443213201
65021502001555
7540112316633
oct122102770457
931406442528
1011023413551
11474747a837
1221778762bb
131068a34717
14768046dc3
15447b6691b
hex2910bf12f

11023413551 has 2 divisors, whose sum is σ = 11023413552. Its totient is φ = 11023413550.

The previous prime is 11023413539. The next prime is 11023413553. The reversal of 11023413551 is 15531432011.

11023413551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11023413551 is a prime.

Together with 11023413553, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11023413551.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11023413553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511706775 + 5511706776.

It is an arithmetic number, because the mean of its divisors is an integer number (5511706776).

Almost surely, 211023413551 is an apocalyptic number.

11023413551 is a deficient number, since it is larger than the sum of its proper divisors (1).

11023413551 is an equidigital number, since it uses as much as digits as its factorization.

11023413551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 11023413551 its reverse (15531432011), we get a palindrome (26554845562).

The spelling of 11023413551 in words is "eleven billion, twenty-three million, four hundred thirteen thousand, five hundred fifty-one".