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110240023 is a prime number
BaseRepresentation
bin1101001001000…
…10000100010111
321200102202212211
412210202010113
5211210140043
614534454251
72506011325
oct644420427
9250382784
10110240023
1157255a63
1230b04387
1319aba6aa
14108d8d15
159a28a9d
hex6922117

110240023 has 2 divisors, whose sum is σ = 110240024. Its totient is φ = 110240022.

The previous prime is 110239981. The next prime is 110240029. The reversal of 110240023 is 320042011.

It is a strong prime.

It is an emirp because it is prime and its reverse (320042011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110240023 - 217 = 110108951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110239985 and 110240012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110240029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55120011 + 55120012.

It is an arithmetic number, because the mean of its divisors is an integer number (55120012).

Almost surely, 2110240023 is an apocalyptic number.

110240023 is a deficient number, since it is larger than the sum of its proper divisors (1).

110240023 is an equidigital number, since it uses as much as digits as its factorization.

110240023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 110240023 is about 10499.5248940131. The cubic root of 110240023 is about 479.4902328275.

Adding to 110240023 its reverse (320042011), we get a palindrome (430282034).

The spelling of 110240023 in words is "one hundred ten million, two hundred forty thousand, twenty-three".