Base | Representation |
---|---|
bin | 1010000010000110111010… |
… | …0100101100111010000100 |
3 | 1110001120210102201001011010 |
4 | 2200201232210230322010 |
5 | 2421214131232143022 |
6 | 35243420142242220 |
7 | 2215662445331523 |
oct | 240415644547204 |
9 | 43046712631133 |
10 | 11031331131012 |
11 | 35733a7923415 |
12 | 12a1b42586370 |
13 | 620333503b2a |
14 | 2a1cc26c64ba |
15 | 141e3c0c250c |
hex | a086e92ce84 |
11031331131012 has 144 divisors (see below), whose sum is σ = 27513569801088. Its totient is φ = 3428001884160.
The previous prime is 11031331130983. The next prime is 11031331131083. The reversal of 11031331131012 is 21013113313011.
It is a super-2 number, since 2×110313311310122 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11031331131012.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12578484318 + ... + 12578485194.
It is an arithmetic number, because the mean of its divisors is an integer number (191066456952).
Almost surely, 211031331131012 is an apocalyptic number.
11031331131012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11031331131012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13756784900544).
11031331131012 is an abundant number, since it is smaller than the sum of its proper divisors (16482238670076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11031331131012 is a wasteful number, since it uses less digits than its factorization.
11031331131012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2366 (or 1487 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 11031331131012 its reverse (21013113313011), we get a palindrome (32044444444023).
The spelling of 11031331131012 in words is "eleven trillion, thirty-one billion, three hundred thirty-one million, one hundred thirty-one thousand, twelve".
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