110324113 has 2 divisors, whose sum is σ = 110324114. Its totient is φ = 110324112.

The previous prime is 110324107. The next prime is 110324119. The reversal of 110324113 is 311423011.

It is a balanced prime because it is at equal distance from previous prime (110324107) and next prime (110324119).

It can be written as a sum of positive squares in only one way, i.e., 68178049 + 42146064 = 8257^2 + 6492^2 .

It is an emirp because it is prime and its reverse (311423011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110324113 is a prime.

It is not a weakly prime, because it can be changed into another prime (110324119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55162056 + 55162057.

It is an arithmetic number, because the mean of its divisors is an integer number (55162057).

Almost surely, 2^110324113 is an apocalyptic number.

It is an amenable number.

110324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110324113 is an equidigital number, since it uses as much as digits as its factorization.

110324113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 110324113 is about 10503.5285975714. The cubic root of 110324113 is about 479.6121186452.

Adding to 110324113 its reverse (311423011), we get a palindrome (421747124).

The spelling of 110324113 in words is "one hundred ten million, three hundred twenty-four thousand, one hundred thirteen".