Base | Representation |
---|---|
bin | 10100100011011010… |
… | …00100001000010011 |
3 | 1001111000020211221111 |
4 | 22101231010020103 |
5 | 140044304204212 |
6 | 5022534234151 |
7 | 540305141365 |
oct | 122155041023 |
9 | 31430224844 |
10 | 11034444307 |
11 | 4752724367 |
12 | 217b4b5957 |
13 | 106b0c74b3 |
14 | 7696b8d35 |
15 | 448ae4ea7 |
hex | 291b44213 |
11034444307 has 2 divisors, whose sum is σ = 11034444308. Its totient is φ = 11034444306.
The previous prime is 11034444263. The next prime is 11034444347. The reversal of 11034444307 is 70344443011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11034444307 is a prime.
It is a super-2 number, since 2×110344443072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11034444347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5517222153 + 5517222154.
It is an arithmetic number, because the mean of its divisors is an integer number (5517222154).
Almost surely, 211034444307 is an apocalyptic number.
11034444307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11034444307 is an equidigital number, since it uses as much as digits as its factorization.
11034444307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 11034444307 its reverse (70344443011), we get a palindrome (81378887318).
The spelling of 11034444307 in words is "eleven billion, thirty-four million, four hundred forty-four thousand, three hundred seven".
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