Base | Representation |
---|---|
bin | 10100100100000100… |
… | …10000100100111101 |
3 | 1001111101201010100122 |
4 | 22102002100210331 |
5 | 140102220002232 |
6 | 5023253304325 |
7 | 540403311563 |
oct | 122202204475 |
9 | 31441633318 |
10 | 11040000317 |
11 | 4755879705 |
12 | 21813350a5 |
13 | 106c2c1388 |
14 | 76a323a33 |
15 | 449341312 |
hex | 29209093d |
11040000317 has 2 divisors, whose sum is σ = 11040000318. Its totient is φ = 11040000316.
The previous prime is 11040000247. The next prime is 11040000347. The reversal of 11040000317 is 71300004011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10851597241 + 188403076 = 104171^2 + 13726^2 .
It is a cyclic number.
It is not a de Polignac number, because 11040000317 - 218 = 11039738173 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11040000295 and 11040000304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11040000347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520000158 + 5520000159.
It is an arithmetic number, because the mean of its divisors is an integer number (5520000159).
Almost surely, 211040000317 is an apocalyptic number.
It is an amenable number.
11040000317 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040000317 is an equidigital number, since it uses as much as digits as its factorization.
11040000317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 11040000317 its reverse (71300004011), we get a palindrome (82340004328).
The spelling of 11040000317 in words is "eleven billion, forty million, three hundred seventeen", and thus it is an aban number.
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