1104071117 has 2 divisors, whose sum is σ = 1104071118. Its totient is φ = 1104071116.

The previous prime is 1104071041. The next prime is 1104071119. The reversal of 1104071117 is 7111704011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1019780356 + 84290761 = 31934^2 + 9181^2 .

It is a cyclic number.

It is not a de Polignac number, because 1104071117 - 2¹² = 1104067021 is a prime.

Together with 1104071119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1104071092 and 1104071101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104071119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552035558 + 552035559.

It is an arithmetic number, because the mean of its divisors is an integer number (552035559).

Almost surely, 2^1104071117 is an apocalyptic number.

It is an amenable number.

1104071117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104071117 is an equidigital number, since it uses as much as digits as its factorization.

1104071117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 196, while the sum is 23.

The square root of 1104071117 is about 33227.5656195274. The cubic root of 1104071117 is about 1033.5520424909.

Adding to 1104071117 its reverse (7111704011), we get a palindrome (8215775128).

The spelling of 1104071117 in words is "one billion, one hundred four million, seventy-one thousand, one hundred seventeen".