1104121222133 has 4 divisors (see below), whose sum is σ = 1104243004800. Its totient is φ = 1103999439468.

The previous prime is 1104121222129. The next prime is 1104121222163. The reversal of 1104121222133 is 3312221214011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1104121222133 - 2² = 1104121222129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104121222099 and 1104121222108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1104121222103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60877733 + ... + 60895866.

It is an arithmetic number, because the mean of its divisors is an integer number (276060751200).

Almost surely, 2^{1104121222133} is an apocalyptic number.

It is an amenable number.

1104121222133 is a deficient number, since it is larger than the sum of its proper divisors (121782667).

1104121222133 is an equidigital number, since it uses as much as digits as its factorization.

1104121222133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121782666.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1104121222133 its reverse (3312221214011), we get a palindrome (4416342436144).

The spelling of 1104121222133 in words is "one trillion, one hundred four billion, one hundred twenty-one million, two hundred twenty-two thousand, one hundred thirty-three".