1104124400413 has 2 divisors, whose sum is σ = 1104124400414. Its totient is φ = 1104124400412.

The previous prime is 1104124400411. The next prime is 1104124400443. The reversal of 1104124400413 is 3140044214011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 885004918009 + 219119482404 = 940747^2 + 468102^2 .

It is an emirp because it is prime and its reverse (3140044214011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1104124400413 - 2¹ = 1104124400411 is a prime.

It is a super-3 number, since 3×1104124400413³ (a number of 37 digits) contains 333 as substring.

Together with 1104124400411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104124400411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552062200206 + 552062200207.

It is an arithmetic number, because the mean of its divisors is an integer number (552062200207).

Almost surely, 2^{1104124400413} is an apocalyptic number.

It is an amenable number.

1104124400413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104124400413 is an equidigital number, since it uses as much as digits as its factorization.

1104124400413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1104124400413 its reverse (3140044214011), we get a palindrome (4244168614424).

The spelling of 1104124400413 in words is "one trillion, one hundred four billion, one hundred twenty-four million, four hundred thousand, four hundred thirteen".