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11042040131 = 97327113453
BaseRepresentation
bin10100100100010100…
…00010100101000011
31001111112112202110022
422102022002211003
5140103230241011
65023405124055
7540426535553
oct122212024503
931445482408
1011042040131
114756a42201
122181b5962b
13106c856975
1476a6d5163
154495e58db
hex292282943

11042040131 has 4 divisors (see below), whose sum is σ = 11042250912. Its totient is φ = 11041829352.

The previous prime is 11042040109. The next prime is 11042040137. The reversal of 11042040131 is 13104024011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13104024011 = 131008001847.

It is a cyclic number.

It is not a de Polignac number, because 11042040131 - 218 = 11041777987 is a prime.

It is a super-2 number, since 2×110420401312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11042040137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40601 + ... + 154053.

It is an arithmetic number, because the mean of its divisors is an integer number (2760562728).

Almost surely, 211042040131 is an apocalyptic number.

11042040131 is a deficient number, since it is larger than the sum of its proper divisors (210781).

11042040131 is an equidigital number, since it uses as much as digits as its factorization.

11042040131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210780.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11042040131 its reverse (13104024011), we get a palindrome (24146064142).

The spelling of 11042040131 in words is "eleven billion, forty-two million, forty thousand, one hundred thirty-one".

Divisors: 1 97327 113453 11042040131