11043320600531 has 4 divisors (see below), whose sum is σ = 11424124759200. Its totient is φ = 10662516441864.

The previous prime is 11043320600471. The next prime is 11043320600537. The reversal of 11043320600531 is 13500602334011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11043320600531 - 2¹⁸ = 11043320338387 is a prime.

It is a super-2 number, since 2×11043320600531² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (29), and also a Moran number because the ratio is a prime number: 380804158639 = 11043320600531 / (1 + 1 + 0 + 4 + 3 + 3 + 2 + 0 + 6 + 0 + 0 + 5 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11043320600494 and 11043320600503.

It is not an unprimeable number, because it can be changed into a prime (11043320600537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190402079291 + ... + 190402079348.

It is an arithmetic number, because the mean of its divisors is an integer number (2856031189800).

Almost surely, 2^{11043320600531} is an apocalyptic number.

11043320600531 is a deficient number, since it is larger than the sum of its proper divisors (380804158669).

11043320600531 is an equidigital number, since it uses as much as digits as its factorization.

11043320600531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380804158668.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 11043320600531 its reverse (13500602334011), we get a palindrome (24543922934542).

The spelling of 11043320600531 in words is "eleven trillion, forty-three billion, three hundred twenty million, six hundred thousand, five hundred thirty-one".