11044002131 has 2 divisors, whose sum is σ = 11044002132. Its totient is φ = 11044002130.

The previous prime is 11044002113. The next prime is 11044002133. The reversal of 11044002131 is 13120044011.

It is a happy number.

Together with previous prime (11044002113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11044002131 is a prime.

It is a super-2 number, since 2×11044002131² (a number of 21 digits) contains 22 as substring.

Together with 11044002133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11044002133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522001065 + 5522001066.

It is an arithmetic number, because the mean of its divisors is an integer number (5522001066).

Almost surely, 2^11044002131 is an apocalyptic number.

11044002131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11044002131 is an equidigital number, since it uses as much as digits as its factorization.

11044002131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11044002131 its reverse (13120044011), we get a palindrome (24164046142).

The spelling of 11044002131 in words is "eleven billion, forty-four million, two thousand, one hundred thirty-one".