Base | Representation |
---|---|
bin | 10100100101110010… |
… | …10011101110010101 |
3 | 1001112101212021201000 |
4 | 22102321103232111 |
5 | 140114413244000 |
6 | 5024530453513 |
7 | 540640054113 |
oct | 122271235625 |
9 | 31471767630 |
10 | 11054431125 |
11 | 4762a357a1 |
12 | 2186134299 |
13 | 10722a490a |
14 | 76c1dcab3 |
15 | 44a742000 |
hex | 292e53b95 |
11054431125 has 64 divisors (see below), whose sum is σ = 20529100800. Its totient is φ = 5869540800.
The previous prime is 11054431121. The next prime is 11054431147. The reversal of 11054431125 is 52113445011.
11054431125 is a `hidden beast` number, since 1 + 1 + 0 + 544 + 3 + 112 + 5 = 666.
It is not a de Polignac number, because 11054431125 - 22 = 11054431121 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11054431121) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 765724 + ... + 780026.
It is an arithmetic number, because the mean of its divisors is an integer number (320767200).
Almost surely, 211054431125 is an apocalyptic number.
11054431125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11054431125 is a deficient number, since it is larger than the sum of its proper divisors (9474669675).
11054431125 is a wasteful number, since it uses less digits than its factorization.
11054431125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14556 (or 14540 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 11054431125 its reverse (52113445011), we get a palindrome (63167876136).
The spelling of 11054431125 in words is "eleven billion, fifty-four million, four hundred thirty-one thousand, one hundred twenty-five".
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