Base | Representation |
---|---|
bin | 10100100110000000… |
… | …01110010101000011 |
3 | 1001112112021101112211 |
4 | 22103000032111003 |
5 | 140120344302120 |
6 | 5025033402551 |
7 | 540661344424 |
oct | 122300162503 |
9 | 31475241484 |
10 | 11056244035 |
11 | 4763a63871 |
12 | 2186869457 |
13 | 107278ab45 |
14 | 76c55164b |
15 | 44a99e25a |
hex | 29300e543 |
11056244035 has 4 divisors (see below), whose sum is σ = 13267492848. Its totient is φ = 8844995224.
The previous prime is 11056244011. The next prime is 11056244047. The reversal of 11056244035 is 53044265011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11056244035 - 213 = 11056235843 is a prime.
It is a super-3 number, since 3×110562440353 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11056243988 and 11056244006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1105624399 + ... + 1105624408.
It is an arithmetic number, because the mean of its divisors is an integer number (3316873212).
Almost surely, 211056244035 is an apocalyptic number.
11056244035 is a deficient number, since it is larger than the sum of its proper divisors (2211248813).
11056244035 is an equidigital number, since it uses as much as digits as its factorization.
11056244035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2211248812.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 11056244035 in words is "eleven billion, fifty-six million, two hundred forty-four thousand, thirty-five".
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