11100011111113 has 2 divisors, whose sum is σ = 11100011111114. Its totient is φ = 11100011111112.

The previous prime is 11100011111107. The next prime is 11100011111159. The reversal of 11100011111113 is 31111111000111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7424769374649 + 3675241736464 = 2724843^2 + 1917092^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11100011111113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11100011111093 and 11100011111102.

It is not a weakly prime, because it can be changed into another prime (11100011121113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550005555556 + 5550005555557.

It is an arithmetic number, because the mean of its divisors is an integer number (5550005555557).

Almost surely, 2^{11100011111113} is an apocalyptic number.

It is an amenable number.

11100011111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100011111113 is an equidigital number, since it uses as much as digits as its factorization.

11100011111113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 13.

Adding to 11100011111113 its reverse (31111111000111), we get a palindrome (42211122111224).

The spelling of 11100011111113 in words is "eleven trillion, one hundred billion, eleven million, one hundred eleven thousand, one hundred thirteen".