Base | Representation |
---|---|
bin | 1010000110000111000110… |
… | …1001001011001101101111 |
3 | 1110022011022012102212001011 |
4 | 2201201301221023031233 |
5 | 2423331002120041421 |
6 | 35335152211130051 |
7 | 2223645610121635 |
oct | 241416151131557 |
9 | 43264265385034 |
10 | 11100102112111 |
11 | 359a588299391 |
12 | 12b33358a3927 |
13 | 62697313675c |
14 | 2a5367db7355 |
15 | 143b148644e1 |
hex | a1871a4b36f |
11100102112111 has 2 divisors, whose sum is σ = 11100102112112. Its totient is φ = 11100102112110.
The previous prime is 11100102112093. The next prime is 11100102112133. The reversal of 11100102112111 is 11121120100111.
11100102112111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11100102112111 - 223 = 11100093723503 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11100102112091 and 11100102112100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100102112811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550051056055 + 5550051056056.
It is an arithmetic number, because the mean of its divisors is an integer number (5550051056056).
Almost surely, 211100102112111 is an apocalyptic number.
11100102112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100102112111 is an equidigital number, since it uses as much as digits as its factorization.
11100102112111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 11100102112111 its reverse (11121120100111), we get a palindrome (22221222212222).
The spelling of 11100102112111 in words is "eleven trillion, one hundred billion, one hundred two million, one hundred twelve thousand, one hundred eleven".
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