Base | Representation |
---|---|
bin | 1010000110000111111011… |
… | …0100001100001001100010 |
3 | 1110022011212121021101000010 |
4 | 2201201332310030021202 |
5 | 2423331430203301310 |
6 | 35335230143505350 |
7 | 2223654232404126 |
oct | 241417664141142 |
9 | 43264777241003 |
10 | 11100323103330 |
11 | 359a69100935a |
12 | 12b33978b8256 |
13 | 6269a9b603a6 |
14 | 2a53894a1586 |
15 | 143b28e68320 |
hex | a187ed0c262 |
11100323103330 has 128 divisors (see below), whose sum is σ = 26876165472000. Its totient is φ = 2934082371584.
The previous prime is 11100323103301. The next prime is 11100323103361. The reversal of 11100323103330 is 3330132300111.
It is a junction number, because it is equal to n+sod(n) for n = 11100323103297 and 11100323103306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1346632189 + ... + 1346640431.
It is an arithmetic number, because the mean of its divisors is an integer number (209970042750).
Almost surely, 211100323103330 is an apocalyptic number.
11100323103330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11100323103330 is an abundant number, since it is smaller than the sum of its proper divisors (15775842368670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11100323103330 is a wasteful number, since it uses less digits than its factorization.
11100323103330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9348.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 11100323103330 its reverse (3330132300111), we get a palindrome (14430455403441).
The spelling of 11100323103330 in words is "eleven trillion, one hundred billion, three hundred twenty-three million, one hundred three thousand, three hundred thirty".
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