Base | Representation |
---|---|
bin | 11001001111011010010100… |
… | …001000100101101101100011 |
3 | 112120001110202101220120000211 |
4 | 121033122110020211231203 |
5 | 104022242402230341003 |
6 | 1032033215250154551 |
7 | 32245136330114461 |
oct | 3117322410455543 |
9 | 476043671816024 |
10 | 111010210012003 |
11 | 3240a190581235 |
12 | 1054a632882a57 |
13 | 49c32aa908903 |
14 | 1d5accc377831 |
15 | cc796c4bc96d |
hex | 64f694225b63 |
111010210012003 has 2 divisors, whose sum is σ = 111010210012004. Its totient is φ = 111010210012002.
The previous prime is 111010210011977. The next prime is 111010210012021. The reversal of 111010210012003 is 300210012010111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111010210012003 - 213 = 111010210003811 is a prime.
It is a super-2 number, since 2×1110102100120032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111010210052003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505105006001 + 55505105006002.
It is an arithmetic number, because the mean of its divisors is an integer number (55505105006002).
Almost surely, 2111010210012003 is an apocalyptic number.
111010210012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
111010210012003 is an equidigital number, since it uses as much as digits as its factorization.
111010210012003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 111010210012003 its reverse (300210012010111), we get a palindrome (411220222022114).
The spelling of 111010210012003 in words is "one hundred eleven trillion, ten billion, two hundred ten million, twelve thousand, three".
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