Base | Representation |
---|---|
bin | 11001001111011010010100… |
… | …001000100101101101101101 |
3 | 112120001110202101220120001012 |
4 | 121033122110020211231231 |
5 | 104022242402230341023 |
6 | 1032033215250155005 |
7 | 32245136330114504 |
oct | 3117322410455555 |
9 | 476043671816035 |
10 | 111010210012013 |
11 | 3240a190581244 |
12 | 1054a632882a65 |
13 | 49c32aa908910 |
14 | 1d5accc37783b |
15 | cc796c4bc978 |
hex | 64f694225b6d |
111010210012013 has 4 divisors (see below), whose sum is σ = 119549456936028. Its totient is φ = 102470963088000.
The previous prime is 111010210012003. The next prime is 111010210012021. The reversal of 111010210012013 is 310210012010111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11817733162249 + 99192476849764 = 3437693^2 + 9959542^2 .
It is not a de Polignac number, because 111010210012013 - 26 = 111010210011949 is a prime.
It is a super-2 number, since 2×1110102100120132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111010210012003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4269623461988 + ... + 4269623462013.
It is an arithmetic number, because the mean of its divisors is an integer number (29887364234007).
Almost surely, 2111010210012013 is an apocalyptic number.
111010210012013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
111010210012013 is a deficient number, since it is larger than the sum of its proper divisors (8539246924015).
111010210012013 is an equidigital number, since it uses as much as digits as its factorization.
111010210012013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8539246924014.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 111010210012013 its reverse (310210012010111), we get a palindrome (421220222022124).
The spelling of 111010210012013 in words is "one hundred eleven trillion, ten billion, two hundred ten million, twelve thousand, thirteen".
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