Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …101111110110100011011 |
3 | 10221010101121221212002011 |
4 | 100021313311332310123 |
5 | 121142002210431021 |
6 | 2205551205050351 |
7 | 143126421012031 |
oct | 20116765766433 |
9 | 3833347855064 |
10 | 1110112202011 |
11 | 39888344103a |
12 | 15b1923b69b7 |
13 | 808b5abc167 |
14 | 3ba304b6551 |
15 | 1dd23623de1 |
hex | 10277d7ed1b |
1110112202011 has 2 divisors, whose sum is σ = 1110112202012. Its totient is φ = 1110112202010.
The previous prime is 1110112201909. The next prime is 1110112202053. The reversal of 1110112202011 is 1102022110111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1110112202011 - 213 = 1110112193819 is a prime.
It is a super-2 number, since 2×11101122020112 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1110112201982 and 1110112202000.
It is not a weakly prime, because it can be changed into another prime (1110112202081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555056101005 + 555056101006.
It is an arithmetic number, because the mean of its divisors is an integer number (555056101006).
Almost surely, 21110112202011 is an apocalyptic number.
1110112202011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110112202011 is an equidigital number, since it uses as much as digits as its factorization.
1110112202011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1110112202011 its reverse (1102022110111), we get a palindrome (2212134312122).
The spelling of 1110112202011 in words is "one trillion, one hundred ten billion, one hundred twelve million, two hundred two thousand, eleven".
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