Base | Representation |
---|---|
bin | 10100101011011000… |
… | …00110010110010000 |
3 | 1001122200001110212102 |
4 | 22111230012112100 |
5 | 140213413100422 |
6 | 5033323215532 |
7 | 542046331310 |
oct | 122554062620 |
9 | 31580043772 |
10 | 11101300112 |
11 | 47874380a1 |
12 | 21999775a8 |
13 | 107bc04b46 |
14 | 77451d440 |
15 | 44e8ee192 |
hex | 295b06590 |
11101300112 has 20 divisors (see below), whose sum is σ = 24581450496. Its totient is φ = 4757700000.
The previous prime is 11101300109. The next prime is 11101300127. The reversal of 11101300112 is 21100310111.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 11101300093 and 11101300102.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49559264 + ... + 49559487.
Almost surely, 211101300112 is an apocalyptic number.
It is an amenable number.
11101300112 is an abundant number, since it is smaller than the sum of its proper divisors (13480150384).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11101300112 is an equidigital number, since it uses as much as digits as its factorization.
11101300112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99118766 (or 99118760 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 11101300112 its reverse (21100310111), we get a palindrome (32201610223).
Subtracting 11101300112 from its reverse (21100310111), we obtain a palindrome (9999009999).
The spelling of 11101300112 in words is "eleven billion, one hundred one million, three hundred thousand, one hundred twelve".
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