1110132000413 has 2 divisors, whose sum is σ = 1110132000414. Its totient is φ = 1110132000412.

The previous prime is 1110132000371. The next prime is 1110132000427. The reversal of 1110132000413 is 3140002310111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 804298667929 + 305833332484 = 896827^2 + 553022^2 .

It is a cyclic number.

It is not a de Polignac number, because 1110132000413 - 2¹⁴ = 1110131984029 is a prime.

It is a super-3 number, since 3×1110132000413³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1110132000391 and 1110132000400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110132000473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555066000206 + 555066000207.

It is an arithmetic number, because the mean of its divisors is an integer number (555066000207).

Almost surely, 2^{1110132000413} is an apocalyptic number.

It is an amenable number.

1110132000413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110132000413 is an equidigital number, since it uses as much as digits as its factorization.

1110132000413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1110132000413 its reverse (3140002310111), we get a palindrome (4250134310524).

The spelling of 1110132000413 in words is "one trillion, one hundred ten billion, one hundred thirty-two million, four hundred thirteen", and thus it is an aban number.