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11102013413 is a prime number
BaseRepresentation
bin10100101011011101…
…10100011111100101
31001122201101201022222
422111232310133211
5140214103412123
65033350402125
7542055362021
oct122556643745
931581351288
1011102013413
114787884aa7
12219a060345
13107c0c470a
14774667381
1544e9e06c8
hex295bb47e5

11102013413 has 2 divisors, whose sum is σ = 11102013414. Its totient is φ = 11102013412.

The previous prime is 11102013371. The next prime is 11102013493. The reversal of 11102013413 is 31431020111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10795833409 + 306180004 = 103903^2 + 17498^2 .

It is a cyclic number.

It is not a de Polignac number, because 11102013413 - 216 = 11101947877 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11102013391 and 11102013400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11102013493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551006706 + 5551006707.

It is an arithmetic number, because the mean of its divisors is an integer number (5551006707).

Almost surely, 211102013413 is an apocalyptic number.

It is an amenable number.

11102013413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102013413 is an equidigital number, since it uses as much as digits as its factorization.

11102013413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11102013413 its reverse (31431020111), we get a palindrome (42533033524).

The spelling of 11102013413 in words is "eleven billion, one hundred two million, thirteen thousand, four hundred thirteen".