11102121012020 has 12 divisors (see below), whose sum is σ = 23314454125284. Its totient is φ = 4440848404800.

The previous prime is 11102121012019. The next prime is 11102121012053. The reversal of 11102121012020 is 2021012120111.

It can be written as a sum of positive squares in 2 ways, for example, as 2416675448356 + 8685445563664 = 1554566^2 + 2947108^2 .

It is a super-3 number, since 3×11102121012020³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11102121011986 and 11102121012004.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 277553025281 + ... + 277553025320.

It is an arithmetic number, because the mean of its divisors is an integer number (1942871177107).

Almost surely, 2^{11102121012020} is an apocalyptic number.

11102121012020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11102121012020 is an abundant number, since it is smaller than the sum of its proper divisors (12212333113264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11102121012020 is a wasteful number, since it uses less digits than its factorization.

11102121012020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 555106050610 (or 555106050608 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 11102121012020 its reverse (2021012120111), we get a palindrome (13123133132131).

The spelling of 11102121012020 in words is "eleven trillion, one hundred two billion, one hundred twenty-one million, twelve thousand, twenty".