Base | Representation |
---|---|
bin | 1010000110001111010101… |
… | …0000110010000001111101 |
3 | 1110022101000002112221002122 |
4 | 2201203311100302001331 |
5 | 2423400012414410023 |
6 | 35340155252332325 |
7 | 2224054412363456 |
oct | 241436520620175 |
9 | 43271002487078 |
10 | 11102310310013 |
11 | 35a051080812a |
12 | 12b38513140a5 |
13 | 626c35778630 |
14 | 2a54d738a12d |
15 | 143be36502c8 |
hex | a18f543207d |
11102310310013 has 4 divisors (see below), whose sum is σ = 11956334180028. Its totient is φ = 10248286440000.
The previous prime is 11102310309997. The next prime is 11102310310027. The reversal of 11102310310013 is 31001301320111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4455700387609 + 6646609922404 = 2110853^2 + 2578102^2 .
It is a cyclic number.
It is not a de Polignac number, because 11102310310013 - 24 = 11102310309997 is a prime.
It is a super-2 number, since 2×111023103100132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11102310309973 and 11102310310000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11102310310033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427011934988 + ... + 427011935013.
It is an arithmetic number, because the mean of its divisors is an integer number (2989083545007).
Almost surely, 211102310310013 is an apocalyptic number.
11102310310013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11102310310013 is a deficient number, since it is larger than the sum of its proper divisors (854023870015).
11102310310013 is an equidigital number, since it uses as much as digits as its factorization.
11102310310013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 854023870014.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11102310310013 its reverse (31001301320111), we get a palindrome (42103611630124).
The spelling of 11102310310013 in words is "eleven trillion, one hundred two billion, three hundred ten million, three hundred ten thousand, thirteen".
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