Search a number
-
+
11103047 = 25394373
BaseRepresentation
bin101010010110…
…101101000111
3202220002111222
4222112231013
510320244142
61033550555
7163242254
oct52265507
922802458
1011103047
1162a397a
12387545b
1323b9967
14169042b
15e94bd2
hexa96b47

11103047 has 4 divisors (see below), whose sum is σ = 11109960. Its totient is φ = 11096136.

The previous prime is 11103019. The next prime is 11103061. The reversal of 11103047 is 74030111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 74030111 = 89831799.

It is a cyclic number.

It is not a de Polignac number, because 11103047 - 212 = 11098951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11103077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353 + ... + 4725.

It is an arithmetic number, because the mean of its divisors is an integer number (2777490).

Almost surely, 211103047 is an apocalyptic number.

11103047 is a deficient number, since it is larger than the sum of its proper divisors (6913).

11103047 is an equidigital number, since it uses as much as digits as its factorization.

11103047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6912.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 11103047 is about 3332.1234971111. The cubic root of 11103047 is about 223.0903198119.

Adding to 11103047 its reverse (74030111), we get a palindrome (85133158).

The spelling of 11103047 in words is "eleven million, one hundred three thousand, forty-seven".

Divisors: 1 2539 4373 11103047