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11103131312000 = 27537137625777
BaseRepresentation
bin1010000110010010011000…
…1100101001111110000000
31110022110010022102011002122
42201210212030221332000
52423403203103441000
635340412541303412
72224113641651330
oct241444614517600
943273108364078
1011103131312000
1135a08a2193072
1212b3a40264b68
136270368a2a20
142a55744210c0
15143c40775085
hexa1926329f80

11103131312000 has 256 divisors, whose sum is σ = 33975586270080. Its totient is φ = 3513957580800.

The previous prime is 11103131311969. The next prime is 11103131312003. The reversal of 11103131312000 is 21313130111.

It is a self number, because there is not a number n which added to its sum of digits gives 11103131312000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11103131312003) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2356889 + ... + 5268888.

Almost surely, 211103131312000 is an apocalyptic number.

11103131312000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11103131312000 is an abundant number, since it is smaller than the sum of its proper divisors (22872454958080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11103131312000 is an equidigital number, since it uses as much as digits as its factorization.

11103131312000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7625826 (or 7625804 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11103131312000 its reverse (21313130111), we get a palindrome (11124444442111).

The spelling of 11103131312000 in words is "eleven trillion, one hundred three billion, one hundred thirty-one million, three hundred twelve thousand".